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51 people (a1,a2,......,a51) meet and shake hands in a circular fashion. In other words, there are totally 51 handshakes involving the pairs (a1, a2),(a2,a3),......,(a50,a51),(a51,a1). Then the size of the smallest set of people such that the rest have shaken hands with at least one person in the set is

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total set of people sake hand=51/3=17
since in odd set we divide by 3
but in even divide by 2;
13 years agoHelpfull: Yes(9) No(0)

people 51/3=17
13 years agoHelpfull: Yes(4) No(2)
so.. 51/3 = 27
13 years agoHelpfull: Yes(0) No(18)

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