Q. Raju has 6 balls. Out of which 4 green 2 blue. He'll pick 2 balls.. Whats probability dat it contain 1 blue and 1 green..

• {2c1*4c1}/6c2= 8/15
• 11 years agoHelpfull: Yes(45) No(0)
• (2/6*4/5)+ (4/6*2/5)=8/15
• 11 years agoHelpfull: Yes(16) No(1)
• (4c1*2c1)/6c2
  =>8/15
• 11 years agoHelpfull: Yes(6) No(0)
• PROBABILITY=(4C1+2C1)/6C2=2/5
• 11 years agoHelpfull: Yes(2) No(5)
• (2/6*4/5)+ (4/6*2/5)=8/15
• 11 years agoHelpfull: Yes(2) No(1)
• (4c1*2c1)/6c2 = 8/15
• 10 years agoHelpfull: Yes(2) No(0)
• sample space= 6c2
  event= 4c1*2c1
  so P(1 blue and 1 green) = 4c1*2c1/ 6c2 = 1/45
• 9 years agoHelpfull: Yes(2) No(0)
• Ans is (2C1*4C1+2C2)/6C2=3/5
• 11 years agoHelpfull: Yes(1) No(1)
• n(s)=6c2,n(E)=4c1*2c1
  n(E)/n(S).
• 11 years agoHelpfull: Yes(0) No(4)
• its 4c1*2c1=8
• 9 years agoHelpfull: Yes(0) No(1)
• n (s) = 6C2 =15 n (a) = 4C1 * 2C1 =8
  so , p(a) = 8/(15)
• 9 years agoHelpfull: Yes(0) No(0)