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Cryptography
AFTER+TWO=YEARS
CALCULATE: Y+E+A+R+S????
Read Solution (Total 10)
-
- AFTER=49703
TWO =+ 728
YEARS=50431
Y+E+A+R+S=13 - 11 years agoHelpfull: Yes(5) No(0)
- Ans: 13
A F T E R
T W O
A=4
F=9
T=7
E=0
R=3
O=8
W=2
USIN CRYPT ARITH MATIC ADD, AFTER+RWO=YEARS
SO, YEARS=13 IS THE WRITE ANSWER
- 11 years agoHelpfull: Yes(4) No(2)
- 49703+728=50431 so ,y+e+a+r+s=13
- 11 years agoHelpfull: Yes(2) No(1)
- let A=0,F=1,T=2,E=3,R=4
T=2(already),w=5,o=6
so, Y+E+A+R+S= 7+3+0+5+8 =24.......(as above values and y=7 &s=8) - 11 years agoHelpfull: Yes(1) No(2)
- 10 or 9
A=0,B=1,C=2.....(9+1)=10
A=1.B=2,C=3......(8+1)=9 - 11 years agoHelpfull: Yes(0) No(3)
- PLEASE ELABORATE HOW ARE U CONSIDERING A=4 / F=9 / T=7 / .................????
- 11 years agoHelpfull: Yes(0) No(0)
- Anyone pls explain the ans1
- 11 years agoHelpfull: Yes(0) No(0)
- @shubham why u dont take r=3,o=7?
- 11 years agoHelpfull: Yes(0) No(0)
- plz someone tell me how u can take a=4,f=9,t=7,e=0.....plz help
- 11 years agoHelpfull: Yes(0) No(0)
- 49703+728=50431
so 5+0+4+3+1=13 - 10 years agoHelpfull: Yes(0) No(0)
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