3 years ago Jacob's age was twice John's age. 3 years hence Jacob's age will be 4/3 times the age of John's. Find Jacob's present age in binary numbers.

• 3 years ago, let jacob's age = A and John's age =B,
  then
  A=2B and A+6= (B+6)*4/3
  
  solving these eqns , we get A =6
  so present age of Jacob = 6+3= 9 years = 1001 years in Binary numbers
• 13 years agoHelpfull: Yes(7) No(1)
• x be present age of jacob,y be present age of john.
  3 years before: x-3=2(y-3) ...(1)
  present jacob=x,john=y ...(2)
  3 years hence: x+3=(4/3)*(y+3)....(3)
  from (1) x=2(y-3)+3...(4)
  substituting (4) in(3)
  we get y=6
  x=9
  therefore
  jacob=9 years
• 12 years agoHelpfull: Yes(1) No(1)