Q There are 7men and 5women sitting in a circle fin all the possible way so that 2women will not

6!7C5=147
first we need to arrange 7 men in cyclic format MMMMMMM and then placed 1 women between 2 men MWMWMWMWMW. SO THIS IS THE CORRECT WAY TO IMPLEMENT THIS QUESTION.
10 years agoHelpfull: Yes(7) No(2)
(7!)7p5
as they are in circle..first men should b arranged.so 7!
later remaining 5 gals shd b arranged in 7 remaining gap between them..

so ans is 7! *(7p5)
10 years agoHelpfull: Yes(5) No(3)
(7-1)!* 7!
10 years agoHelpfull: Yes(2) No(1)
(7-1)!*7P5= 720*2520=1814400
10 years agoHelpfull: Yes(2) No(0)
Arranging 7 men on a circle means
(n-1)! i.e. 6! &
now after placing all men on circle we have 7 vacant places where we can arrange 5 women
And for arranging 5 women out of 7 places we have 7P5 ways
Therefore answer would be 6!*7P5.
10 years agoHelpfull: Yes(2) No(0)
(7+1)p5 * 7!
10 years agoHelpfull: Yes(1) No(2)
the answre is 7! for 7 mens now there vl be 8 places hence placing 5 women in 5 places is 8p5
10 years agoHelpfull: Yes(1) No(1)
7!*9p2
(gap betn 7 men=9)
10 years agoHelpfull: Yes(0) No(21)
solution : 7!*7C5
7 men in 7 places in a circle can be arranged in 7! ways
5 women can pick up any 5 places among 7 places between
10 years agoHelpfull: Yes(0) No(4)

Q. There are 7men and 5women sitting in a circle fin all the possible way so that 2women will not sit together