Q. Waht is the next number of the following sequence
1,1/2,3/2,2,5,1/3,16/3,15,12,1/4,43/4,?

• 43/4 should be 49/4 as 12+ 1/4=49/4
  (1,1/2,3/2,2),(5,1/3,16/3,15),(12,1/4,49/4,X)
  [1+(3/2-1/2)*1=2]
  [5+(16/3-1/3)*2=15]
  [12+(49/4-1/4)*3=48=x]
• 10 years agoHelpfull: Yes(26) No(6)
• sorry guys,
  ans: look at the 1st and the 4th numbers in each sequence....
  12x4=48 is the ans
• 10 years agoHelpfull: Yes(16) No(1)
• divide series into 3 sections, in which each section contains 4 digits
  4th terms in each section will be 1*2,5*3,12*4
  so last number in the series =12*4=48
• 10 years agoHelpfull: Yes(5) No(0)
• (1,1/2,1/3,2),..
  3rd no.(1+1/2)=3/2
  4th no.=1x2=2
  
  next set of 4 4th no.=1stx3=5x3=15
  same way ans 12x4=48
• 10 years agoHelpfull: Yes(4) No(2)
• There is an alternate solution:
  
  Each 4th number is the previous number numerator minus the before the previous number numerator.
  
  1/2,3/2 -> 3-1=2
  1/3,16/3->16-1=15
  1/4,43/4->43-1=42
  
  So the answer could also be 42.
  
  If as Rakesh says it's 49/4 instead of 43/4 then the answer is 48 (49-1=48).
• 8 years agoHelpfull: Yes(4) No(0)
• its just the summation of the two factors i the series....
  1 1/2 3/2 2
  5 1/3 16/3 15
  12 1/4 43/4 ? ans: (43/4)+(1/4)=11
• 10 years agoHelpfull: Yes(2) No(9)
• Diff bw 2 & 5 is 3 and 15 & 12 is 3 so after 4 & next num diff should be 3...so answer is 1
• 9 years agoHelpfull: Yes(0) No(2)
• 1+1/2+3/2+2=5,5+1/3+1/3=16/3
  15+12+1/4+43/4=38,38+43/4+43/4=119/2
• 8 years agoHelpfull: Yes(0) No(1)