Q. Given the sequence a, bb, ccc, dddd, eeeee....... and so on, find the 240th term of the sequence?

• a,bb,ccc,dddd,eeeee.......
  a(1),bb(2),ccc(3),dddd(4),eeeee(5).......
  1+2+3+4+5+...n=240
  => n(n+1)/2 =240
  => n(n+1)=480
  if n=21, 21*22=462
  if n=22, 22*23=506
  U=21, V=22
  so the 240 th term should be 22th letter or V.
• 11 years agoHelpfull: Yes(11) No(0)
• 234 is divisible by 26,it means total alphabets are 26
  remaining 6th letter is f
• 11 years agoHelpfull: Yes(1) No(5)
• 240 times 'f'
• 11 years agoHelpfull: Yes(0) No(5)