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Exam
Logical Reasoning
Logical Sequences
Q. Given the sequence a, bb, ccc, dddd, eeeee....... and so on, find the 240th term of the sequence?
Read Solution (Total 3)
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- a,bb,ccc,dddd,eeeee.......
a(1),bb(2),ccc(3),dddd(4),eeeee(5).......
1+2+3+4+5+...n=240
=> n(n+1)/2 =240
=> n(n+1)=480
if n=21, 21*22=462
if n=22, 22*23=506
U=21, V=22
so the 240 th term should be 22th letter or V. - 10 years agoHelpfull: Yes(11) No(0)
- 234 is divisible by 26,it means total alphabets are 26
remaining 6th letter is f - 10 years agoHelpfull: Yes(1) No(5)
- 240 times 'f'
- 10 years agoHelpfull: Yes(0) No(5)
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