Q. How many arrangements can be made if there are 5 balls from which 3 are red, 1 is green, 1 is yellow. find the probability of getting all 3?

• arrangement = 5!/3!=20
  Probability of getting all 3 balls=
  3 from 5=5c3
  1 from 3 red ball,1 green,1 yellow
  (3c1*1c1*1c1)/5c3 =3/10
  is the 2nd ans 3/10????
• 10 years agoHelpfull: Yes(37) No(2)
• total no of arrangments ::
  
  (considering arrangment of all 5 balls)
  5 balls can be arranged in !5 but 3 are of same in color so 5!/3!=20
  
  probability part ::
  
  (considering probability of getting all 3 red balls)
  since p=favorable cases/total cases
  so probability of getting all 3 red balls is 1 (favorable)
  and total cases will be selecting any 3 balls out of 5 ie 5C3
  hence p=1/5C3 = 1/10
• 10 years agoHelpfull: Yes(11) No(2)
• Arrangement = 5!/3! = 20
  P(All colour) = (3C1*1C1*1C1)/5C3 =3/10
• 10 years agoHelpfull: Yes(5) No(0)
• 3/10 will be the answer
• 10 years agoHelpfull: Yes(2) No(0)
• tanushree ghosh...........u know .....the value of 1c1 ....infinity
  
• 10 years agoHelpfull: Yes(1) No(15)
• total number of arrangements = 5c5
  
  prob of gettn all 3 = 5c3
  
  5c5/5c3=1/10 answer is 1/10
  
• 10 years agoHelpfull: Yes(1) No(0)
• 9
  3c1*1*1*3
• 10 years agoHelpfull: Yes(0) No(5)
• arrangements will be 60
  and probability will be 3/5
• 10 years agoHelpfull: Yes(0) No(7)
• value of 1C1 is infinity?? :O :O from when ??
• 10 years agoHelpfull: Yes(0) No(4)
• question toh thik likho...
• 10 years agoHelpfull: Yes(0) No(0)
• 5!/3!=20
  out of 5,3 r similar
• 10 years agoHelpfull: Yes(0) No(0)