Q. A man whose bowling average is 12.4, takes 5 wickets for 26 runs and there by decreases his average by 0.4. the number of wickets taken by him before his last match is?

• 12.4*x+26=(5+x)12
  solve equation x=85
  so 85 wicket is ans
• 10 years agoHelpfull: Yes(15) No(0)
• Let the wickets claimed by him before the last match be x.
  Total runs he had given = x X 12.4 = 12.4x
  Number of wickets now taken by him = (x + 5)
  12(x + 5) = 12.4x + 26
  ⇒ 12x + 60 + 12.4x + 26
  ⇒ 0.4x = 34
  ⇒ x = 340/4 = 85
  Wickets taken by him before his last match = 85
• 10 years agoHelpfull: Yes(15) No(0)
• 5 because before his last match his bowling average was 12.4 and he took 5 wickets
• 10 years agoHelpfull: Yes(1) No(5)
• total no. of runs before = 12.4*x
  where x = no. of wickets taken before these match
  now
  12.4*x+26/x+5=12 (total runs/total wicket = new avg)
  solve the eqn x=85 ans.
  
• 10 years agoHelpfull: Yes(1) No(0)