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(3X+2)(2X-5)=AX^2+ KX+N;
THEN WHAT IS THE VALUE OF A-N+K?
Read Solution (Total 4)
-
- (3x+2)(2x-5)=6x^2-11x-10
So,A=6, K=-11, N=-10
Finally,
A-N+K=6-(-10)+(-11)
=6+10-11
=5
- 12 years agoHelpfull: Yes(7) No(2)
- (3x-2)(2x-5)= 6x2-11x-10
A=6, K=-11, n= -10
A-N+K= 6+11-10= 5 - 12 years agoHelpfull: Yes(3) No(1)
- 6x^2-11x-10
A=6 K=-11 N=-10
A-N+K = 5 - 12 years agoHelpfull: Yes(3) No(2)
- Simplify LHS..
(3x+2)(2x−5)=6x2−11x−10=ax2−n+k
(
3
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+
2
)
(
2
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−
5
)
=
6
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2
−
11
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−
10
=
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2
−
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+
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...
equate the coefficients...
a=6 ; k = -11 and n = -10..
so a−n+k=6−(−10)+(−11)=6+10−11=5 - 8 Months agoHelpfull: Yes(0) No(0)
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