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A speaks truth 70% of the time; B speaks truth 80% of the time.What is the probability that both are contradicting each other?

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when A speak truth than B have to speak wrong....when B speak truth than A speak to wrong..
p=0.7*0.2+0.3*0.8=0.38 answer
13 years agoHelpfull: Yes(19) No(0)

A SPEAKS TRUTH 70% SO LIE IN 30% ,B SPEAKS TRUTH IN 80% so lie in 20% .PROBABILITY OF CONTRADICTING=(70/100)*(20 /100)+(80/100)*(30/100)=34%
13 years agoHelpfull: Yes(4) No(6)
let assume p(a)=probability of A to speak truth
p(b)=probability of B to speak truth
Similarly,p(a')=to tell lie
p(b')=tell a lie
p(a)=0.7,p(b)=0.8
p(a')=0.3,p(b')=0.2
p(e)=p(a)*p(b')+p(a')*p(b)=9/25
13 years agoHelpfull: Yes(1) No(2)

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