Determine an A.P. whose 3rd term is 16 and when 5th term is subtracted from 7th term, we get 12.

• let a be 1st term n d be the common difference
  
  3rd term= a+2d=16
  5th term= a+4d
  7th term= a+6d
  
  7th term - 5th term= 2d=12
  => d=6
  
  hence a+2d=16
  => a=4
  
  hence AP is 4, 10, 16, 22, 28, 34, 40......
• 15 years agoHelpfull: Yes(1) No(1)
• 4,10,16,22,28,34,40,46...
• 15 years agoHelpfull: Yes(1) No(2)
• 4,10,16,22,28,34,40,46,...
• 15 years agoHelpfull: Yes(0) No(1)