Q. If a car starts from A to B with some velocity.After travelling some distance 30km,engine damaged,and the car goes with 4/5 of its actual velocity.The car reaches B 45min later to actual time.If the car engine fails after travelling 45km distance,car reaches B 36min late to the actual time.What is the intial vel of the car and Distance between A and B

• let total distance is x kmph
  speed is same fr 2 cases,those are after failing engine
  so, we can take (x-30)/(45/60)=(x-45)/(36/60)
  4(x-30)=5(x-45)
  4x-120=5x-225
  by solving, x=105km(total distance)
  
  
• 10 years agoHelpfull: Yes(23) No(1)
• time taken by car in first case to cover 15 km is 9 min more than it took to cover same distance in second case
  therefore,
  case 1: distance=15 km
  speed= (4/5)xkmph
  time= t+(9/60)hr
  case 2: distance= 15 km
  speed = x kmph
  time= t
  now both the cases we can derive the following equation
  (4x/5)(t+3/20)=xt
  t= 3/5 hr
  now we can calculate speed of the car
  x= 15/(3/5)=25 kmph
  
• 10 years agoHelpfull: Yes(4) No(16)
• distance is 300km
  n speed is 100 km/hr
  
• 10 years agoHelpfull: Yes(1) No(5)
• velocity is 100 km/hr.....
• 10 years agoHelpfull: Yes(1) No(1)
• vel of car is 100km/hr and total distance between A and B is 105 km.
  
• 10 years agoHelpfull: Yes(1) No(1)
• distance=130 km ; speed=20 kmph
• 8 years agoHelpfull: Yes(1) No(0)
• http://avinash-iete.blogspot.in/2011/03/ibm-placement-paper.html
• 8 years agoHelpfull: Yes(1) No(0)