Q. Find the least number of candidates in an examination so that the percentage of successful candidates should be 76.8%:

• suppose no. of total candidates are 'y' and successful are 'x'.
  (x/y)*(100)=76.8 or x/y=0.768
  or y=x/0.768
  here we need minimum value of y, which is obtained by minimum value of x.
  if put x=768 then y=1000
  now we will try decrease value of x than we will find less value of y. so factorized 768 by 2 further.
  if put x=384 then y=500
  if put x=192 then y=250
  if put x=96 then y=125(answer)
  if put x=48 then y=62.5(not integer)
  so ans is 125(minimum)
• 10 years agoHelpfull: Yes(30) No(1)
• answer is 125
  
  bcoz...
  No. of successful candidates = 76.8% of x
  x = total students =(768/(10*100))*x = (96/125)x
  Which must be a whole no.
  The reqd least no. = 125
• 10 years agoHelpfull: Yes(25) No(12)
• 125.
  Let x be the total students.
  76.8x/100 = integer
  It should be integer.
  (384/5)x/100 = 96x/125
  From this we get x should be min value 125.
• 10 years agoHelpfull: Yes(4) No(9)
• 76.8----------->100(suppose out of 100 students 76.8 students are passed )
  so multiply both by 5 to make it a whole number
  384------------>500
  and now divide the both no. by 2
  so we get 96----------->125
• 7 years agoHelpfull: Yes(4) No(0)
• let total candidate is x
  no of successful candidate 76.8%
  pass candidate is y
  (x/y)*(100)=76.8 or x/y=0.768
  or y=x/0.768
  here we need minimum value of y, which is obtained by minimum value of x.
  if put x=768 then y=1000
  now we will try decrease value of x than we will find less value of y. so factorized 768 by 2 further.
  put x=384 then y=500
  put x=192 then y=250
  put x=96 then y=125(answer)
  put x=48 then y=62.5
  62.5 is not integer
  so answer is 125
  
  
  
• 9 years agoHelpfull: Yes(1) No(0)
• 100 will be
• 9 years agoHelpfull: Yes(0) No(6)
• 125.
  Let x be the total students.
  76.8x/100 = integer
  It should be integer.
  (384/5)x/100 = 96x/125
  From this we get x should be min value 125.
  
• 9 years agoHelpfull: Yes(0) No(0)
• success percentage is 76.8,so multiply in by 5 to get whole number then the least number of candidates in 384
  
• 8 years agoHelpfull: Yes(0) No(3)