Q. A merchant buys two articles for Rs.600. He sells one of them at a profit of 22% and the other at a loss of 8% and makes no profit or loss in the end. What is the selling price of the article that he sold at a loss?
Option
A) Rs. 404.80
B) Rs.440
C) Rs. 536.80
D) Rs. 160

• Let C1 be the cost price of the first article and C2 be the cost price of the second article.
  Let the first article be sold at a profit of 22%, while the second one be sold at a loss of 8%.
  
  We know, C1 + C2 = 600.
  The first article was sold at a profit of 22%. Therefore, the selling price of the first article = C1 + (22/100)C1 = 1.22C1
  The second article was sold at a loss of 8%. Therefore, the selling price of the second article = C2 - (8/100)C2 = 0.92C2.
  
  The total selling price of the first and second article = 1.22C1 + 0.92C2.
  
  As the merchant did not make any profit or loss in the entire transaction, his combined selling price of article 1 and 2 is the same as the cost price of article 1 and 2.
  
  Therefore, 1.22C1 + 0.92C2 = C1+C2 = 600
  As C1 + C2 = 600, C2 = 600 - C1. Substituting this in 1.22C1 + 0.92C2 = 600, we get
  1.22C1 + 0.92(600 - C1) = 600
  or 1.22C1 - 0.92C1 = 600 - 0.92*600
  or 0.3C1 = 0.08*600 = 48
  or C1 = 48/(0.3) = 160.
  If C1 = 160, then C2 = 600 - 160 = 440.
  The item that is sold at loss is article 2. The selling price of article 2 = 0.92*C2 = 0.92*440 = 404.80.
  
• 10 years agoHelpfull: Yes(46) No(4)
• ok in this ,
  x+y=600---1st equation
  x*(100+22)/100+y*(100-8)/100=600----second equation...
  
  now solve the x and y...
  and at the end ...440*92/100=404.8
• 10 years agoHelpfull: Yes(28) No(5)
• answer is B ie 440
  
  becoz..
  given that after sold two articles net effect is no profit no loss condition
  so
  let selling price of the article that he sold at a loss is x
  then
  0.92x+1.22(600-x)=600
  0.92-1.22x+732=600
  -0.3x=-132
  x=132/0.3
  
  x=440
  
  hence Rs 440
  
• 10 years agoHelpfull: Yes(10) No(13)
• CP(total)= 600
  two articles are there.
  let cost price of them CP1=x, CP2=y
  so x+y=600 ---------- (1)
  
  SP= (100+gain%)CP/100
  SP= (100-loss%)CP/100
  
  so SP1= (100+22)x/100= 122x/100
  SP2= (100-08)y/100= 92y/100
  
  since no profit, no loss so CP(total)=SP(total)
  122x/100 + 92y/100 = 600 ---------(2)
  
  by solving eq 1 and 2
  x=160, y=440
  
  so selling price of the article that he sold at a loss=
  
  SP2= (92/100)*440 = 404.80
• 10 years agoHelpfull: Yes(5) No(0)
• Answer is B
  Because If price of one article is 'x' and other one is 'y'.Then
  x+y=600..............equation 1
  One article sells on profit of 22%
  So x+.22x=1.22x
  Other one sells on loss of 8%
  So y-.08y=.92y
  Now no profit no loss state that's why
  
  1.22x+.92y=600............equation 2
  From equation 1 and 2
  x=160 and y=440
• 10 years agoHelpfull: Yes(3) No(7)
• ANS : 160
  
• 10 years agoHelpfull: Yes(2) No(2)
• 440
  by checking given conditions
• 10 years agoHelpfull: Yes(1) No(11)
• let cp of 1article=x,
  cp of 2article=600-x
  122%ofx+92%of(600-x)=600,
  x=160
• 10 years agoHelpfull: Yes(1) No(4)
• let x be the price of item sold in profit y be the price of item sold in loss
  
  so x+y=600
  and 122% of x + 92% of y =600
  or 1.22x + 0.92y = 600
  
  solving this we get 440
• 9 years agoHelpfull: Yes(1) No(1)
• ans is 440.
  
  x+y=600-------(1)
  22% of x=8%of y
  
  x/y=8/22=4/11-------(2)
  
  By solving (1) and (2),we get y=440
• 5 years agoHelpfull: Yes(0) No(0)
• C1 + C2 = 600
  first article = C1 + (22/100)C1 = 1.22C1
  second article = C2 - (8/100)C2 = 0.92C2
  first and second article = 1.22C1 + 0.92C2
  22C1 + 0.92C2 = C1+C2 = 600
  C1 + C2 = 600, C2 = 600 - C1. Substituting this in 1.22C1 + 0.92C2 = 600, we get
  1.22C1 + 0.92(600 - C1) = 600
  C1 = 160, then C2 = 600 - 160 = 440
  The selling price of article 2 = 0.92*C2 = 0.92*440 = 404.80.
• 5 years agoHelpfull: Yes(0) No(0)