A group of labourers promise to do a piece of work in 12 days, but 5 of them do not turn up. If rest of the group do the work in 18 days, Find the original number of men.

a.15

b.25

c.35

d.45

• 12x = 18(x-5)
  12x = 18x - 90
  90 = 18x - 12x
  90 = 6x
  x= 15
• 12 years agoHelpfull: Yes(6) No(1)
• x12=(x-5)18 =45
• 12 years agoHelpfull: Yes(2) No(3)
• CASE 1:
  as 12 men will do the work in -18 days.
  so 1 man do the work in -12*8 days
  
  CASE2:
  
• 11 years agoHelpfull: Yes(1) No(3)
• 15 is correct. Let W be the work. x be the original number of men.
  eqn 1. W=12x
  eqn 2. W=18(x-5)
  Thus 12x=18x-90
  Solving we get x=15
  
• 8 years agoHelpfull: Yes(1) No(0)
• 1 day work for x men=1/12*x
  1 day work for x-5 men=1/18(x-5)
  1/12*x=1/18(x-5)=15
  
• 11 years agoHelpfull: Yes(0) No(0)