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Q. A circular metal plate of even thickness has 12 holes of radius 1 cm drilled into it. As a result the plate lost 1/6th its original weight. The radius of the circular plate is
Option
(a) 16sqrt2
(b) 8sqrt2
(c) 32sqrt2
(d) sqrt72
Read Solution (Total 1)
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- (d) sqrt72
Area of 12 holes=12*Pi*1^2=12*Pi
As 12*Pi=(1/6)th weight,so total Area of Plate=12*Pi/(1/6)=72*Pi
If r=radius of the plate,then its Area=Pi*r^2=72*Pi, So r=Sqrt72 - 10 years agoHelpfull: Yes(1) No(0)
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