Q There are five same model cars parked in the same direction in parking If 3 cars are red 1

5!/(3!*1!*1!) = (5*4*3*2*1)/(3*2*1) = 120/6 = 20 ways.
10 years agoHelpfull: Yes(17) No(0)
5 cars can be arranged as 5!
and 3 cars are of same colour
so, 5!/3!=20
10 years agoHelpfull: Yes(12) No(0)
5! ways=120 ways
10 years agoHelpfull: Yes(4) No(9)
Given that there are 5 cars ,if all cars are of same model, then
they can be arranged in
5!=120 ways
10 years agoHelpfull: Yes(2) No(4)
5!/(3!*1!*1!)=20
10 years agoHelpfull: Yes(2) No(0)
5!=120 ways
10 years agoHelpfull: Yes(1) No(1)
hey wat was the correct answer 20 r 120 im confused
10 years agoHelpfull: Yes(1) No(1)
answer is 20 friends sure
10 years agoHelpfull: Yes(1) No(0)
Required no is 5!/3!=20 confirm
10 years agoHelpfull: Yes(1) No(0)
as its about permutation (arrangement) so 5 different car can arrange ,
5!/(3!*1!*1!)way=20 ways
10 years agoHelpfull: Yes(1) No(0)
5 same model cars
3=red, 1=black, 1=green
so, 5!/3! * 1! * 1! = 5!/3! = 20
9 years agoHelpfull: Yes(1) No(0)
they can be arranged in 5! ways i.e., 5*4*3*2*1=120
10 years agoHelpfull: Yes(0) No(3)
there are 3m and 3n not 2 n
9 years agoHelpfull: Yes(0) No(0)

Q. There are five same model cars parked in the same direction in parking. If 3 cars are red, 1 is black and 1 is green, in how many ways they can be arranged in the parking?