Q. In an isosceles triangle, the sides are 13cm, 13cm, 10cm which is inscribed insiade a circle. Find the radius of the circle?

• sides are, a=13,b=13,c=10
  s=(13+13+10)/2=18
  area of triangle=[18(18-13)(18-13)(18-10)]^1/2 = (18*5*5*8)^1/2 =60 cm^2
  R be the radius then it will be circumradius of triangle
  R=(a*b*c)/(4*area of triangle)
  R=(13*13*10)/(4*60)=7.04cm
• 10 years agoHelpfull: Yes(2) No(1)
• inscribed circle radius (r)= 3.75
• 10 years agoHelpfull: Yes(0) No(0)
• perimeter of triangle= perimeter of a circle
  13+13+10 = 2*pi*r
  36 = 2*pi*r
  pi*r = 18
  r = 5.729 cm ans...
• 10 years agoHelpfull: Yes(0) No(1)
• Given a=13 , b=13, c=10
  So, According to triangle property:-
  Area of the triangle=a*b*c/4R
  where R is circumcenter
  so area of triangle=[18(18-13)(18-13)(18-10)]^1/2 = (18*5*5*8)^1/2 =60 cm^2
  R=a*b*c/4*area of the triangle
  R=(13*13*10)/(4*60)
  R=7.04 cm
• 10 years agoHelpfull: Yes(0) No(0)