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Time and Work
Q. Two pipes A and B can fill a tank in 36 hours and 46 hours respectively. If both the pipes are opened simultaneously, how much time will be taken to fill the tank?
Read Solution (Total 7)
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- a fill in one hour = 1/36
b fill in one hour = 1/46
both fill in one hour = 1/36+1/46
= 82/1656
time taken by both pipes = 1656/82
=20.195 hrs ans... - 10 years agoHelpfull: Yes(33) No(1)
- In a hour A can fill 1/36 part of the tank
Similarly B can fill 1/46 th part of the tank
then together they can fill is the addition of both what they fill in a hour
1/36+1/46=82/1656
and thus reversing the solution 1656/82=20 hours and 19 min ,they both can fill
- 10 years agoHelpfull: Yes(4) No(2)
- x*y/x+y
36*46/36+46
- 10 years agoHelpfull: Yes(2) No(0)
- Total unit=828
efficiency of A=23 unit & B=18 unit.
so, (A+B)=41 unit
time req. to fill tha tank= 828/41=20.2 hours.
- 9 years agoHelpfull: Yes(2) No(0)
- 20h and 19mins
- 10 years agoHelpfull: Yes(1) No(4)
- A pipe can fill a tank in =36 hours.
A pipe can fill a tank in 1 hour =1/36
similarly
B pipe can fill a tank in =45 hours.
B pipe can fill a tank in 1 hour=1/45
Together A and B can fill a tank in one hour=1/36+1/45=81/36*45=1/20
which mean A and B togther fill the tank in 20 hours - 10 years agoHelpfull: Yes(1) No(1)
- 18*46/41hours
- 10 years agoHelpfull: Yes(0) No(0)
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