Q. Solve
after+two=years, then y+e+a+r+s=??

• A F T E R
  + T W O
  ----------
  Y E A R S
  
  4 9 7 0 3
  + +7 2 8
  ----------
  5 0 4 3 1
• 11 years agoHelpfull: Yes(2) No(0)
• ans = 13
  
  A F T E R + T W O = Y E A R S
  4 9 7 0 3 + 7 2 8 = 5 0 4 3 1
  
  => Y+E+A+R+S = 5+0+4+3+1 = 13
• 11 years agoHelpfull: Yes(0) No(0)
• how does after become 49703 and two become 728????
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• @ PRAGATI
  A F T E R
  + T W O
  ---------
  Y E A R S
  
  4 9 7 0 3
  + 7 2 8
  ----------
  5 0 4 3 1
  
  guys if u notice the question then u'll get that "F = E" it means the value of 'F' is changed to 'E' and it is possible when the previous iteration carry 1.
  but in the nxt iteration, value of 'A' is also changed to 'Y' it means the previous iteration i.e 'F' carry 1, and the previous iteration have only one alphabet i.e 'F' and its carry 1 then the value of 'F = 9' and whatever value will come from previous iteration i.e 'T + T' must carry 1 then it will satisfy the values "F=9,E=0"now put these value in the respective alphabet.
  
  now check the last column i.e "R+O=S" also check the nxt column too i.e "E+W=R" and u know the value of 'E=0' from here u've to find 'W=R' and if u notice then u'll identify that the value if 'W' is changed to 'R' it means its carry 1 from its previous iteration i.e "R+O=S" then the value of 'S' must be greater than 10 then it will carry 1.
  now check what are the possible value will give more than 10 and remember 9 and 0 already assign to F and E respectively. So '8+2=10' is not possible,
  '8+3=11' it is possible and it carry 1 then assign the value of "R=3,O=8 and S=1"
  now check 'E+W=R' u've "E=0,R=3" from here u'll get the value of 'W=2'.
  
  Now check "T+T=A" no matter whatever value of 'A' will come.u've to remember that 'T+T=A' must carry 1.
  if u put '5+5=10' i.e '0' not possible 'E=0' already assign,
  '6+6=12' i.e '2' not possible 'W=2' already assign,
  '7+7=14' i.e '4' it is possible.
  then take the value of "T=7,A=4 and Y=5"
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• 49703
  728
  50431
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