Ssc
Exam
Numerical Ability
Time and Work
Q. Sita can complete a work in 10 days.Geeta is 25% more efficient than Sita and Rita is 60% more efficient than Geeta.How many days will they taken to complete that work
Read Solution (Total 6)
-
- sita complete in 10 day
geeta complete in =10/1.25=8 day
rita complete in 8/1.6=5 days ans
complete work in a day =1/(1/10+1/8+1/5)
=1/(17/40)
40/17 days
2.5 day(approx...) - 10 years agoHelpfull: Yes(8) No(0)
- Ans. Together they take 2.35 days
Sita 10 days 100% efficient
Geeta x days 125% efficient (25% more efficient that Sita)
Rita y days 200% efficient (60% more efficient than Geeta 125*60/100 = 75)
Together they work for Z days 425% efficient
Z = 100/425*10 = 2.35 days
x = 100/125*10 = 8 days
y = 100/200*10 = 5 days - 10 years agoHelpfull: Yes(1) No(0)
- 2*(168/261)days
- 10 years agoHelpfull: Yes(0) No(1)
- sita 1 day work=1/10
gita 1 day work=1/7.5 (as she is 25% efficent than sita,so 25% of 10 is 2.5,(10-2.5=7.5)
similarly rita= 1/4.5
now together they can do=(1/10)+(1/7.5)+(1/4.5)=41/90 part in one day
they can do the work in 90/41 days ie 2(8/41)
- 10 years agoHelpfull: Yes(0) No(1)
- sita...10 days, geeta =7.5 days..rita..3 days so all together (1/10+1/7.5+1/3)=17/ part in one day.. therefore 30/17 days to complete the work
- 10 years agoHelpfull: Yes(0) No(1)
- sita complete in 10 day
geeta complete in =10/1.25=8 day
rita complete in 8/1.6=5 days ans
sita in 10 day
geeta in =10/1.25=8 day
rita in 8/1.6=5
complete work in a day =1/(1/10+1/8+1/5)
=1/(17/40)
40/17 day - 10 years agoHelpfull: Yes(0) No(0)
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