Two cars start from the same point at same time.the first car travels at a constant speed of 12 km/h while the second car travels at an initial speed of 6 km/h,which increases by 1 km/h every hour.what will be the diatance traveled by the second car by the time it meets the first car?

• 156 kms
  
  
  
• 10 years agoHelpfull: Yes(2) No(6)
• after 11 hrs 1st car travels 11x12=132km
  after 11 hrs 2 nd car travels 6x11+1+2+3.....+11=132km(car increases its speed by 1km for 1hr)
  ans:132km
• 10 years agoHelpfull: Yes(1) No(8)
• 156 kms
  13×12=156
  12×6+13+12+11......+1=156
  
  
• 10 years agoHelpfull: Yes(1) No(9)
• to meet the distance 156km at 18hours
• 10 years agoHelpfull: Yes(0) No(5)
• Use sum of 1st n terms of AP
  Sn= n/2[2a+(n-1)d]
  For 1st car a = 12KM/h d = 0
  Sn= n/2[2(12)+(n-1)0]
  = 12n............> Eq
  For 2nd car a = 6KM/h d = 1KM/h
  Sn= n/2[2(6)+(n-1)1]
  =1/2[11n+n^2] ...............> Eq2
  Now equate Eq 1 and Eq 2
  12n = 1/2[11n+n^2]
  24n = 11n+n^2
  13n = n^2
  n = 13
  Substitute n = 13 in any equation
  We get the distance as 156 KM
• 6 years agoHelpfull: Yes(0) No(0)