COMPUTE THE NUMBER OF DISTINCT WAY IN WHICH 56 TOFFEES CAN BE DISTRIBUTED TO 5PERSON A,B,C,D AND E SO THAT NO PERSON RECEIVES LESS THAN 10 TOFFEES(TOFFEE CAN NOT BE DEVIDED)??

• NO PERSON RECEIVES LESS THAN 10 TOFFEES
  so 50 toffees are distributed equally i.e 10 toffees to each of A,B,C,D,E
  now (56-50=6) toffees are to be distributed among 5 persons
  
  we know that
  number of ways in which n identical things can be distributed among r persons, each one of them can get 0,1,2 or more
  =(n+r-1)C(r-1)
  
  here n=6(toffee) is to distributed among r=5(persons)
  
  no. of ways=(6+5-1)C(5-1)=10C4=10C6
  
• 10 years agoHelpfull: Yes(60) No(1)
• ans. 210
  5-1c^6+5-1
• 10 years agoHelpfull: Yes(4) No(0)
• 10C4.Firstly give 10 toffees to each then 6 toffee can be distributed to 5 person as:(6+5-1)C(5-1) = 10C4=140
• 10 years agoHelpfull: Yes(1) No(1)
• 210
  0 0 0 0 6= 5 ways
  0 0 0 1 5= 20 ways
  0 0 1 1 4= 30 ways
  0 0 0 2 4 = 20 ways
  0 1 1 1 3= 20 ways
  0 0 1 2 3= 60 ways
  0 0 0 3 3 =10 ways
  1 1 1 1 2= 5 ways
  0 1 1 2 2=30 ways
  0 0 2 2 2 = 10 ways
  after adding all 210 ans
  also by 10C4= 210
  
• 10 years agoHelpfull: Yes(1) No(0)
• first we will distribute 10 toffees to each of 5 persons i.e total 50 toffees ,
  now remaining toffees are 6 which we have to distribute among 5 person so this can be possible in
  m+r-1 C r-1
  =>6+5-1C5-1=10C4
• 10 years agoHelpfull: Yes(0) No(0)