8+88+888+8888...upto 24 terms.
what are the last three digits?

• 8+88+888+8888...upto 24 terms
  
  simply add
  
  unit digit=(8+8+8+... 24 times)= 24*8=192,
  unit digit=2, carry=19
  
  tenth digit=(8+8+...23 times)+19=184+19=203,
  tenth digit=3, carry=20
  
  hundredth digit=(8+8+...22 times)+20=176+20=196,
  hundredth digit=6 & so on
  
  last three digits= 632
• 10 years agoHelpfull: Yes(133) No(3)
• simply multiply...
  8*24=192(2 unit digit and 19 carry)
  8*23=203(3 unit digit and 20 carry)
  8*22=196(6 unit digit and 19 carry)
  ans=632.
• 10 years agoHelpfull: Yes(6) No(0)
• In unit's place there are 24 8's so,24*8=192
  in ten's place 23 8's so,23*8=184
  in 100's place 22 so,22*8=176
  therefore 632 = (176+20=196)6 (184+19=203)3 (192)2
• 10 years agoHelpfull: Yes(1) No(0)
• simply visualise we have to calculate last three digit so digit before last three is of no use now we will be having 8+88+888+888+888+888+888 upto 24term so we are having 2 term who are not having 8 in all three do keep them aside now 22 term will be having 888 so 888*22 last three digit 536 now add 88 and 8 in it so we will get 632
• 10 years agoHelpfull: Yes(0) No(0)