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Numerical Ability
Quadratic Equations
There are two sides of a rectangle with one large and other small. a person walks along the diagonal and save 1/3 rd of larger side. Difference between larger nd smaller size is 192. then area of the triangle is
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- (1-1/3)x + y=sqrt(x2+y2).......(eq 1)
x-y=196...........(eq 2)
solving (1) and (2) gives x=336 nd y=140
therefore,xy=336*140 ans
[diagonal=underoot of x2 plus y2; save 1/3 means reaching from point a to c of rect walks 2/3 of x plus y] - 10 years agoHelpfull: Yes(4) No(1)
- (1-1/3)x + y=sqrt(x2+y2).......(eq 1)
x-y=196...........(eq 2)
solving (1) and (2) gives x=336 nd y=140
area of triangle= (xy)/2= 23520 - 10 years agoHelpfull: Yes(3) No(0)
- not possible
- 10 years agoHelpfull: Yes(2) No(2)
- Sorry the difference is 196
- 10 years agoHelpfull: Yes(0) No(2)
- 588*392=.......
- 10 years agoHelpfull: Yes(0) No(0)
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