2,6,30,60,130,221...tell 8 dgt in series??

• in this series
  T(n)=n^3+/- n
  + for odd n and - for even n
  n=1 T(n)=1+1=2
  n=2 T(n)=8-2=6
  n=3 T(n)=27+3
  n=4 T(n)=64-4=60
  n=5 T(n)=125+5=130
  n=6 T(n)=216-6=210
  n=7 T(n)=343+7=350
  n=8 T(n)=512-8=504..
  
  so ans is 504
• 10 years agoHelpfull: Yes(34) No(8)
• 520
  (1*1*1)+1 = 2
  (2*2*2)-2 = 6
  (3*3*3)+3 =30
  (4*4*4)-4 =60
  (5*5*5)+5 =130
  (6*6*6)-6 = 210
  ......
• 10 years agoHelpfull: Yes(11) No(7)
• 504
  n^3+n
  n^3-n
  .
  .
  .
  .
  8^3-8=504
• 10 years agoHelpfull: Yes(7) No(3)
• f(n)=(n^3)+n, when n is odd and f(n)=(n^3)-n ,when n is even
  1^3+1=2
  2^3-2=6
  3^3+3=30
  ....
  8^3-8=504(ANS)
• 10 years agoHelpfull: Yes(4) No(1)
• 1^3 +1 =1
  2^3 -2 =6
  3^3 +3 =30
  4^3 -4 =60
  5^3 +5 =130
  6^3 +5 =221
  7^3 -4 =339
  8^3 +3 =515
  9^3 -2 =727
  10^3 +1=1001
• 10 years agoHelpfull: Yes(4) No(0)
• Mr mohan!!!if n=6;6^3-6=210...but in series it is 221 right????
• 10 years agoHelpfull: Yes(3) No(0)