IBM
Company
Numerical Ability
Sequence and Series
1.3,4,12,76,588,?
2.92,48,16,10,6.5,?
3.2,1,2,3,8,0,1,9,1,2,?
Read Solution (Total 8)
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- 2) 92/2=46 46+2=48
16/2=8 8+2=10
6.5/2=3.25 3.25+2=5.25
So 5.25!! - 10 years agoHelpfull: Yes(35) No(4)
- 1)4-3=1
12-4=8(8^1)
76-12=64(8^2)
588-76=512(8^3)
4684-588=4096(8^4)
so answer is 4684 - 10 years agoHelpfull: Yes(20) No(0)
- 3)2^1=2
2^3=8
8^0=1
1^9=1
1^2=1, so ans=1 - 10 years agoHelpfull: Yes(13) No(3)
- 1)4684 3*8=24-20=4
4*8=32-20=12
12*8=96-20=76
76*8=608-20=588
588*8=4704-20=4684 - 10 years agoHelpfull: Yes(6) No(0)
- 3, 4, 12, 76, 588, X
4=3+8^0
12=4+8^1
76=12+8^2
588=76+8^3
X =(588+8^4)= 4684
Give your valuable feedback ;-) :-)
- 8 years agoHelpfull: Yes(2) No(0)
- is the next two term 0,1?
- 10 years agoHelpfull: Yes(0) No(0)
- 3rd one is 4
3+2-(2+1)=2
9+1-(8+0)=2
1+4-(2+1)=2....hence ans is 4
- 10 years agoHelpfull: Yes(0) No(10)
- 1)
3+1:4
4+8:12
12+64:76
76+512:588
588+4096:4684
So ans is 4684
here we are every time increasing power of 8 and adding to the next number
- 8 years agoHelpfull: Yes(0) No(0)
IBM Other Question
5, 6, 6. 5, 7. 5, 7, 7, 8, 9. 5, 8. 5, ?
a woman goes to company 6 days in aweek the bus fare for her 1 day journey is 0.2$,and on every saturday she uses her car to go to office and the expenditure is 3$ how much will be rise of her total expenditure for a week if she uses car to go