like one student takes 20 mins if he go with speed 15kmph and at
what speed he should go to reach in 15 mins ( nos are not same)

• as the distance is same,it is 15kmph*20mins
  now new speed is (15kmph*20mins)/15mins=20Kmph
• 10 years agoHelpfull: Yes(34) No(1)
• 1/4th decrease in the time will result 1/5th increase in speed.So 15+5=20
• 10 years agoHelpfull: Yes(2) No(1)
• more speed less time
  less speed more time
  so,dre exsists indirect relation b/w speed and time
  So,
  20/15=x/15
  x=20
  
  
• 10 years agoHelpfull: Yes(2) No(0)
• If the ratio of the speed of A and B is a:b,then the ratio of the time taken by them to cover the same distance is 1/a:1/b or b:a
  so speed=20kmph
  
• 10 years agoHelpfull: Yes(1) No(0)
• s*t=d;
  15*(20/60)=s*(15/60)
  s=20kmph=5.55m/s
• 10 years agoHelpfull: Yes(1) No(0)
• s1t1=s2t2,as s1=15kmph,t1=20/60=1/3,t2=15/60=1/4,
  by substituting we get 15/3=x*1/4,so
  x=20kmph
• 10 years agoHelpfull: Yes(0) No(0)
• t1=20/60 hr=1/3hr.speed=15kmph,dist=time*speed=15*(1/3)=5km.
  t2=15min i.e.,15/60=1/4hr dist=5km speed=dist/time=5/(1/4)=5*4=20kmph
  ans=20kmph
• 10 years agoHelpfull: Yes(0) No(0)
• Student takes 15mins with the speed of 15kmph to reach certain distance means how much speed he/she will take to reach in 15mins for the same distance= (20/15)*15=20kmph
• 10 years agoHelpfull: Yes(0) No(0)