IBM
Company
Numerical Ability
Clocks and Calendars
First day of 1999 is Sunday what day is the last day
(a)Sunday (b)Monday (c).... (d)cannot be determined.
Read Solution (Total 12)
-
- Last day is also same day as first day unless it is leap year which in case will be next day.
So the answer is Sunday. - 10 years agoHelpfull: Yes(34) No(2)
- 1999 is not a leap year.so it contains 365 days.
365=52*7(weeks)+1(day)
sun mon tue wed thu fri sat
1 2 3 4 5 6 7
so the last 1 day vill be sunday - 10 years agoHelpfull: Yes(11) No(1)
- sunday,1999 in not a leap year
- 10 years agoHelpfull: Yes(7) No(0)
- 2000-1=1999
1600+400-1=1999
0 odd days+6 odd days-1=6-1=5
as per calender the day for number 5 is friday
so ans is FRIDAY
- 10 years agoHelpfull: Yes(7) No(19)
- 1999 is not a leap year,so 365 days
so total 52 weeks,per every week 7 days=52*7+1(day)=365 days
the year starting with sunday so week end with saturday,the remaining day is sunday.the ans is sunday - 10 years agoHelpfull: Yes(5) No(0)
- 1999 is not a leap year so 1 day is odd day so monday is ans
- 10 years agoHelpfull: Yes(4) No(3)
- Monday option-b
- 10 years agoHelpfull: Yes(3) No(6)
- In normala year start with a day and end with same day .so Answer is: A.Sunday
- 10 years agoHelpfull: Yes(3) No(1)
- in non leap year 365 days=7*52+1
As the day is repeat exactly after 7 days
364th days is sunday and 365th days is Monday - 10 years agoHelpfull: Yes(1) No(2)
- ans will be sure 100
- 10 years agoHelpfull: Yes(0) No(5)
- for the first day of 2000 to be monday it should be sunday on last day of 1999
- 10 years agoHelpfull: Yes(0) No(0)
- 1999 is not a leap year.so it contains 365 days.
365=52*7(weeks)+1(day)
mon tue wed thu fri sat sun
1 2 3 4 5 6 7
so the last 1 day vill be Monday
- 9 years agoHelpfull: Yes(0) No(4)
IBM Other Question