Consider the numbers between 300 and 400 such that when each number is divided by 6,9 and 12, it leaves 4 as remainder in each case. What is the SUM of the numbers?

• Consider the numbers such that when each number is divided by 6,9 and 12, it leaves 4 as remainder in each case.
  
  LCM of 6,9,12 is 36.
  The reqd numbers are 4+36*n where n=1,2,3,..... and nos are between 300 and 400.
  so possible values of n are 9 and 10 .( if 400 is not considered)
  Numbers are 328 and 364.
  sum = 692
• 13 years agoHelpfull: Yes(11) No(1)
• 6p+4=9q+4
  p/q=3/2...... 9q+4=12r+4... q/r=4/3
  so p:q:r=6:4:3
  now the no are in bet 300 and 400
  so if we put mulpiple of 6 are 6, 12,....48,54,60...
  so..6*48=288,6*54=324,6*60=360,6*66=396....
  so the nor are 324,360...total=328+364=692
• 13 years agoHelpfull: Yes(1) No(5)