how many words of 11 letters be formed with all the vowels in even places using all the letters of

even places in 11 letter word 2,4,6,8,10
vowels can be placed at even places in 5! ways
rest 21 letters can be placed in remaining 6 places in 21P6 ways

total words formed= 5!* 21P6
10 years agoHelpfull: Yes(12) No(3)

in even places a,e,i,o,u are placed with 5!
and remaining 6 places are filled with 21 letters i.e 21C6

so total words can be formed= 5!*21C6

and if repetition is allowed then the total word formed will be= (5^5*21^6)
10 years agoHelpfull: Yes(3) No(0)
in 11 places,5 are even,so,5 vowels can be arranged at 5 places in 5!=120 ways
now,remaining 21 letters can be arranged at 6 places in 21c6 ways
total no of ways=120*21c6=41184,but this is correct only if repetations are not allowed
10 years agoHelpfull: Yes(1) No(0)
it is not written that repetition is not allowed.
[zazazazazaz is allowed].
am i right rakesh???
10 years agoHelpfull: Yes(0) No(0)
even places in 11 letter word 2,4,6,8,10
vowels can be placed at even places in 5! ways
rest 21 letters can be placed in remaining 6 places in 21P6 ways

total words formed= 5!* 21P6
10 years agoHelpfull: Yes(0) No(0)

how many words of 11 letters be formed with all the vowels in even places using all the letters of the english alphabets