EVER+SINCE=DARWIN then D+A+R+W+I+N=?

• 1. As it's a sum of 3 numbers hence the maximum value of D could be 2 or 1, but then we look at S which could have maximum value 9 and if it gets a carry of 1 then the value of A will be 0 and the D=1.
  2. Then we looks at E and I which results in R, as 9 is already occupied by S so E could be 8 and I could be 7 and R will be 5 with carry 1.
  3. Then we place the values of R=5 and E=8 resulting in N=3 with carry 1.
  4. In ten's digits - E=8 and and value of C could be 3,4,6 (As all others are occupied) and To make I=7 (previously assigned in step 2) E must be added by 9 which is already occupied by S. So this hit ends here.
  Now start again with reduced value of E or I, repeat above steps until you get a correct answer or a dead end.
  5. Repeating above steps one time comes with E=5 and I=7 which results in R=3 carry=1.
  6. Placing R=3 and E=5 in unit digits and their sum gives 8.
  7. in ten's digits place E=5 now you can add 2 to make I=7 hence C=2.
  8. in 100's digits you have N=8 (from step 6) and only digits that are left now are 4 and
  6 hence. So placing V=4 you will get W=2 which is not true because it is already assigned to C. So we are left with only V=6 as the ultimate choice and this leads the result in to W=4.
  
  Hence this way we got the answer
  
  ....5 6 5 3
  ....E V E R
  ..9 7 8 2 5
  + S I N C E
  ----------------------
  D A R W I N
  1 0 3 4 7 8
  
  Hence D+A+R+W+I+N = 1+0+3+4+7+8 =23
• 10 years agoHelpfull: Yes(30) No(2)
• ......5 6 5 3
  ......E V E R
  ...9 7 8 2 5
  + S I N C E
  ----------------------
  D A R W I N
  1 0 3 4 7 8
  
  Hence D+A+R+W+I+N = 1+0+3+4+7+8 =23
• 10 years agoHelpfull: Yes(11) No(8)
• sir plz explain how the numbers 5653 for EVER and 97825 for SINCE came..
• 10 years agoHelpfull: Yes(10) No(0)
• @VAMSI KRISHNA, SRIGAYATRI KANDUKURI, SUVARCHALA
  just do one thing
  give a to z values of 1-0 i.e 1,2,3,4....7,8,9,0
  
  like:
  1 2 3 4 5 6 7 8 9 0
  a b c d e f g h i j k
  L m n o p q r s t u v
  w x y z
  
  by this u can see that
  E=5, V=2, E=5, R=8
  S=9, I=9, N=4, C=3, E=5
  
  5 2 5 8
  +9 9 4 3 5
  ---------------
  1 0 4 6 9 3
  D A R W I N
  
  D+A+R+W+I+N=1+0+4+6+9+3=23 ANS
  
  
• 10 years agoHelpfull: Yes(9) No(19)
• How u guys are alloting numbers to those alphabets??? Plz explain...
• 10 years agoHelpfull: Yes(5) No(0)
• plz explain
  
• 10 years agoHelpfull: Yes(2) No(0)
• please explain
• 10 years agoHelpfull: Yes(1) No(0)
• 9 6 2 7 8
  S I N C E
  8 3 8 4
  E V E R
  ..........
  DA R W I N
  10 4 5 6 2
  = 18
• 10 years agoHelpfull: Yes(1) No(3)
• plz explain
• 10 years agoHelpfull: Yes(0) No(1)
• EVER=7458,SINCE=200235,DARWIN=207693.ANS-27
• 10 years agoHelpfull: Yes(0) No(3)
• E(8)+V(7)+E(8)+R(2)
  S(9)+I(4)+N(5)+C(6)+E(3)
  --------------------------------
  D(1)+A(0)+R(2)+W(3)+I(4)+N(5)=15
• 10 years agoHelpfull: Yes(0) No(4)
• Ahh wats that calculation totally confused !! Can anyone plz tell me wat kind of qus it is??
• 10 years agoHelpfull: Yes(0) No(1)
• @ bagish ::: since cant be more than 5 numbers.
• 10 years agoHelpfull: Yes(0) No(0)
• ever = 5653
  since= 97825
  Darwin=103478
  
  so D+a+r+w+i+n = 23
• 10 years agoHelpfull: Yes(0) No(2)
• a=1,d=4,w=23,r=18,i=9,n=14 total=69*no of letters in the word
  
• 9 years agoHelpfull: Yes(0) No(2)
• 1 2 3 4 5 6 7 8 9 0
  a b c d e f g h i j
  k l m n o p q r s t
  u v w x y z
  
  by this u can see that
  e=5, v=2, e=5, r=8
  s=9, i=9, n=4, c=3, e=5
  
  hence numbers must be unique for each alphabet
  
  5 2 5 8
  +9 9 4 3 5
  ---------------
  1 0 4 6 9 3
  d a r w i n
  
  ans : 1+0+4+6+9+3=23
• 5 years agoHelpfull: Yes(0) No(1)