IBM
Company
Numerical Ability
Sequence and Series
135,486,422,224,140,541,134,431,145,596,421...find next three terms.
Read Solution (Total 6)
-
- Addition of digit :
135: (1+3=[4], 3+5=[8], 5+1=[6])=486
we got (135, 486)
Opposite number of digit:
422= opposite of 224
we got (422, 224)
Addition of digit:
and then next pair 135+5= 140
1+4=[5], 4+0=[4], 0+1=[1]= 541
we got: (140, 541)
Opposite number digit:
and next pair is 134:
134= opposite digit of 431
we got (134, 431)
Addition of digits in form of digit + its next digit:
next pair is: 140+5=145
1+4=[5], 4+5=[9], 5+1=[6] =596
we got= (145, 596)
Opposite number of digit:
now opposite digit of 421=124
we got (421, 124)
and next pair is: 145+5=150
1+5=[6], 5+0=[5], 0+1=[1] =651
so lastly the next number is 124, 150,651...........
- 10 years agoHelpfull: Yes(68) No(0)
- break the series into 3 parts
1st series: 135 486 422 224(its reverse of 3rd number)
2nd series: 140 541 134 431(its reverse of 3rd number)
3rd series: 145 596 421 124(ans)
- 10 years agoHelpfull: Yes(10) No(0)
- as 422 is reversed to 224
likewise 134 is reversed to 431
therefore
421 is reversed to 124
135+5=140
140+145
therefore,145+5=150
486+55=541
541+55=596
therefore,596+55=651
so the next three no.are 124,150,651 - 10 years agoHelpfull: Yes(2) No(0)
- HAI frnds can anybody say how many days it will take to get an offer letter from IBM GBS after selection.
I am selected on 25th jan 2014 in pune(PCCOE college) - 10 years agoHelpfull: Yes(0) No(0)
- roopal my email id hemalatha.con@gmail.com
- 10 years agoHelpfull: Yes(0) No(0)
- 1+3+5=9 4+8+6=18 2nd no is double the first no.
4+2+2=8 2+2+4=8 sum of third n fourth no is same in the 4th no is in the reverse order of third number.
similary 1+4+5=10 and 5+9+6=20 so the sum of next two numbers will be same and the nos will be in reverse order of each other. so the next no. here is 421 so the missing no should be 124 - 10 years agoHelpfull: Yes(0) No(0)
IBM Other Question