3 years ago Jacob's age was twice John's age. 3 years hence Jacob's age will be 4/3 times the age of John. Find Jacob's present age in binary numbers.
1. 100
2. 1001
3. 110
4. 11

• jacob age is x, john's age is y
  3years ago.
  x-3=2(y-3)
  therefore,x=2y-3.
  three years hence
  x+3=4/3(y+3)
  3x+9=4y+12
  3x=4y+3
  6y-9=4y+3
  2y=12->y=6.
  x=2y-3->x=12-3
  x=9(jacob's age)
  in binary form of 9 = 1001
  ans is 2)1001
  
• 13 years agoHelpfull: Yes(2) No(1)
• let jacob age x, john's age y
  3years ago.
  x-3=2(y-3)
  x=2y-3.
  three years later
  x+3=4/3(y+3)
  3x+9=4y+12
  3x=4y+3
  solving the
  6y-9=4y+3
  2y=12->y=6.
  solving, we get
  x=2y-3->x=12-3
  x=9(jacob's age)
  in binary form of 9 = 1001
• 13 years agoHelpfull: Yes(1) No(0)