A number when successively divided by 3,5 and 8 leaves remainder 1,4,and 7 respectively.Find the respective remainders if the order of the divisors be reversed.

• we can find the number by reverse process as.
  reminder 7 and Divisor 8 no. is 8+7 = 15(15 divided by 8 reminder will be 7)
  now number which divide by 5 and leaves reminder 4 with Quotient 15 is
  (15*5)+4 = 79
  same (79*3)+1 = 238.
  now 238/8 = 29 reminder 6
  29/5 = 5 reminder 4
  5/3 = 1 reminder 2
• 10 years agoHelpfull: Yes(0) No(2)
• A number when successively divided by 3,5,8 leaving remainders 1,4,7 can be written as 3(5(8k+7)+4)+1
  
  =>120k+118
  
  when this number is dived by 8 i.e (120k+118)/8=15k+14 remainder 6
  (15k+14)/5=3k+2 remainder 4
  (3k+2)/3=k remainder 2
  And D) 6,4,2
  Hope its clear
• 10 years agoHelpfull: Yes(0) No(0)