Q. What is the next number of the following sequences
1)0.8,1.8,3.6,3.6,4.6,9.2,9.2,10.2,?

2)11,8,17,14,23,24,31,32,?

3)(15*4+3)/4,16,26,(9*5+1)/5,9,19,(64*3+2)/3,65,75,(30*8+3)/8,?(it's like mixed fraction friends where i have mentioned * )

4)3,2,1,4,5,4,5,1,0,6,3,?

5)7.2,2.2,,3.2,16,11,12,60,55,56,?

6)3,5,2,100,4,7,3,196,1,6,5,?

7)2,9,5,49,11,169,?

8)2,6,5,14,11,26,17,?

9)22,19.5,21.45,33,26,15,-1,?

10)1/4,1/4,1/23/2,6,?

11)9,12,4,8,12,15,5,9,3,6,2,6,6,9,?

12)9,4,16,6,36,21,441,?

• 1)0.8,1.8,3.6,3.6,4.6,9.2,9.2,10.2,?
  (0.8,1.8,3.6),(3.6,4.6,9.2),(9.2,10.2,X)
  0.8+1=1.8, 1.8*2=3.6
  3.6+1=4.6, 4.6*2=9.2
  9.2+1=10.2, 10.2*2=X => x=20.4
  
  2)11,8,17,14,23,24,31,32,X
  count prime no.s from 11
  11,13,17,19,23,29,31,37,41,43
  11,8,17,14,23,24,31,32,X,Y
  series is of formed(alternate prime n0.-5)
  so X=41, Y=43-5=38
  
  3)(15*4+3)/4,16,26,(9*5+1)/5,9,19,(64*3+2)/3,65,75,(30*8+3)/8,X,Y
  (15+ 3/4 ,16,26),(9+ 1/5 ,9,19),(64 +2/3 ,65,75),(80 +3/8 , x,y)
  in every group,
  2nd term= approaximation of 1st no.
  3rd term= 2nd no.+10
  
  SO X=approax(80 +3/8)=80
  Y=X+10=80+10=90
  
  4)3,2,1,4,5,4,5,1,0,6,3,?
  (3,2,1),(4,5,4),(5,1,0),(6,3,X)
  in every group 1st term is increasing by +1
  & (3rd term-2nd term=1)
  s0 3-X=1 => x=2
  
  5)7.2,2.2,,3.2,16,11,12,60,55,56,?
  (7.2,2.2,,3.2),(16,11,12),(60,55,56),x
  7.2-2.2=5,2.2+1=3.2,3.2*5=16
  16-11=5,11+1=12, 12*5=60
  60-55=5,55+1=56,56*5=280 => x=280
  
  6)3,5,2,100,4,7,3,196,1,6,5,?
  (3,5,2,100),(4,7,3,196),(1,6,5,x)
  100=(3+5+2)^2
  196=(4+7+3)^2
  x=(1+6+5)^2 => 144
  
  7)2,9,5,49,11,169,x
  prime no.s 2,3,5,7,11,13,17
  2,3^2,5,7^2,11,13^2,x => x=17
  
  8)2,6,5,14,11,26,17,?
  prime n0.s 2,3,5,7,11,13,17,19
  2,3*2,5,7*2,11,13*2,17,x => x=19*2=38
  
  9)22,19.5,21.45,33,26,15,-1,x,y
  (22,33,-1),(19.5,26,x),(21.45,15,y)----- its not clear
  
  
  10) 1/4,1/4,1/2,3/2,6,?
  1/4, (1/4*1),(1/4*2),(1/2*3),(3/2*4),(6*5=x) => x=30
  
  11) 9,4,16,6,36,21,441
  (9,4),(16,6),(36,21),(441,X)
  9=4+5*1
  16=6+5*2
  36=21+5*3
  441=x+5*4 => x=441-20=421
  
  12)9,12,4,8,12,15,5,9,3,6,2,6,6,9,X,Y
  
  (9,12,4,8)(12,15,5,9)(3,6,2,6)(6,9,X,Y)
  9+3=12,12/3=4,4+4=8
  12+3=15,15/3=5,5+4=9
  3+3=6,6/3=2,2+4=7
  
  so 6+3=9, 9/3=X, X+4=Y => X=3, Y=7
  
  
  
  
  
  
  
  
  
  
  
  
  
• 10 years agoHelpfull: Yes(39) No(1)
• correction for 3rd qn
  
  3)(15*4+3)/4,16,26,(9*5+1)/5,9,19,(64*3+2)/3,65,75,(30*8+3)/8,X,Y
  (15+ 3/4 ,16,26),(9+ 1/5 ,9,19),(64 +2/3 ,65,75),(30 +3/8 , x,y)
  in every group,
  2nd term= approaximation of 1st no.
  3rd term= 2nd no.+10
  
  SO X=approax(30 +3/8)=30
  Y=X+10=30+10=40
  
  
• 10 years agoHelpfull: Yes(12) No(1)
• 1. 0.8
  0.8 +1=1.8
  1.8*2=3.6
  3.6+1=4.6
  4.6*2=9.2
  9.2+1=10.2
  10.2*2=20.4
• 10 years agoHelpfull: Yes(5) No(0)
• 12.9,4,16,6,36,21,441,?
  9-4=5
  16-6=10
  36-21=15
  similarly
  441-421=20
  ans 421
  
• 10 years agoHelpfull: Yes(4) No(0)
• 6) 3+5+2=10, 10^2=100
  4+7+3=14, 14^2=196
  1+6+5=12, 12^2=144
  ans 144
• 10 years agoHelpfull: Yes(3) No(0)
• If 45.65
  
  ( 22, 19.5, 21.45), (33, 30.5, 33.55),( 44, 41.5 , x)
  
  first terms of brackets => 22 , 33 , 44
  second terms of brackets => 19.5 , 19.5 + 11 , (19.5 + 11*2)
  third terms of brackets => 21.45 , (21.45 + 12.1) , (21.45 + 2*12.1)
  
  => x = 21.45 + 2 * 12.1 = 45.65
• 10 years agoHelpfull: Yes(3) No(0)
• correction in 9th series 22,19.5,21.45,33, 30.5, 33.55,44, 41.5 ,?
  and the solution is
  divide it into 3 sets
  ( 22, 19.5, 21.45), (33, 30.5, 33.55),( 44, 41.5 , x)
  
  first terms of brackets => 22 , 33 , 44
  second terms of brackets => 19.5 , 19.5 + 11 , (30.5 + 11*2)
  third terms of brackets => 21.45 , (21.45 + 12.1) , (33.55 + 12.1)
  
  => x = 33.55+ 12.1 = 45.65(ans)
  
• 10 years agoHelpfull: Yes(3) No(0)
• 2)11,8,17,14,23,24,31,32,?
  11-3=8
  8+9=17
  17-3=14
  14+9=23
  and
  23+1=24
  24+7=31
  31+1=32
  32+7=41(ans)
• 10 years agoHelpfull: Yes(2) No(4)
• Dear RAKESH
  
  kindly give clarity on the 11 question pls...
• 10 years agoHelpfull: Yes(2) No(3)
• 7) series is of prime numbers
  2,(3^2),5,(7^2),11,(13^2),17,(19^2)
• 10 years agoHelpfull: Yes(1) No(0)
• 1)20.4
  2)39
  3)30
  4)
  5)280
  6)144
  7)17
  8)54
  9)
  10)30
  11)3
  12)421
• 10 years agoHelpfull: Yes(1) No(0)
• 2) 41
  8) 38
  
  Description:
  2) alternative prime series and missing alernate terms...
  11,(13),17,(19),23,(29),31,(37),41
  Note: 39 is not a prime number(3*13=39).
  So answer is 41.
  
  8)This is also related to prime number series.
  But in this the alternate prime number is replaced by (prime number * 2)
  2,(3*2=6),5,(7*2=14),11,(13*2=26),17,(19*2=38)
  So answer is 38...
  Do u agree guys???
  
• 10 years agoHelpfull: Yes(1) No(0)
• 3)divide it into 4 sets
  {9,12,4,8){12,15,5,9,),(3,6,2,6),(6,9,?}
  see 9+3=12
  12/3=4
  4+4=8
  12+3=15
  15/3=5
  5+4=9
  6+3=9
  9/3=3(ans)
• 10 years agoHelpfull: Yes(1) No(0)
• ans 30 mixed fraction 15 3/4 =63/4=15.75~16
  9 1/5 =46/5 = 9.2 ~ 9
  64 2/3 =194/3=64.6 ~ 65
  30 3/8 =243/8 =30.3 ~ 30
  for next series 10 should be added
• 10 years agoHelpfull: Yes(0) No(0)
• 5)
  7.2,2.2,3.2,16,11,12,60,55,56
  3.2*5=16
  12*5=60
  56*5=280 ans
• 10 years agoHelpfull: Yes(0) No(0)
• sorry that is 11 question
• 10 years agoHelpfull: Yes(0) No(0)
• 12)9,4,16,6,36,21,441,?
  (9,4),(16,6),(36,21),(441,?)
  9-4=5*1
  16-6=5*2
  36-21=5*3
  441-?=5*4
  441-20=421
  ans=421
  
• 10 years agoHelpfull: Yes(0) No(0)