A bag contains one rupee, fifty paise and twenty five paise coins, whose values are in the proportion 2:5:7 respectively. If the total number of coins are 400, then find the total value of coins.

• Total no of coins=400
  The bag contains one rupee, fifty paise and twenty five paise coins, whose values are in the proportion 2:5:7 respectively and their numbers are in ratio of 2*1:5*2:7*4 or 2:10:28
  so their numbers are 20,100,280 respectively.
  Total value = 20+100/2 +280/4=20+50+70= Rs 140.
  
  
• 10 years agoHelpfull: Yes(8) No(1)
• total no. of coins=400
  1 re no. of coins =(2/14)*400
  50 p no. of coins =(5/14)*400
  25 p no. of coins =(7/14)*400
  Total value of coins=(2/14)*400*1+(5/14)*400*0.5+(7/14)*400*0.25
  =178.57
• 10 years agoHelpfull: Yes(1) No(4)
• Simply take x as the common value so 1 rupee coin value is 2x 50 paise coin value is 5x and 25 paise coin value is 7x now no. Of coin is if 1 rupee coin is 2x then 50 paise coin is 5×2 x and 25 paise coin is 7×4x.
  (2+10+28)x = 400
  X = 10
  From that 1 rupee coin is 20.
  50 paise coin = 100.
  25 paise coin = 280.
  
• 10 years agoHelpfull: Yes(0) No(1)