Cost of a car is 8378rs in first year,13450rs in second year.from third year onwards every year the price will increse 5% from the previous year cost.Then what will be the cost of car at the end of 5th year.

• first year= 8378
  second year= 13450
  third year= 1.05*13450=14122.5
  fourth year=1.05* 14122.5=14828.625
  fifth year= 1.05* 14828.625= 15570.05 = 15570 (approx)
• 10 years agoHelpfull: Yes(46) No(1)
• 15570.05625
  This question is very simple based on compound interest.
  Cost = p(1+(r÷100))pow n .
  Where p is cost in that year
  R is rate of interest
  N is no. Of years
  In this case p = 13450 r = 5% n= 3 years.
  
  13450(1+(5÷100))^3 = 15570
  
• 10 years agoHelpfull: Yes(20) No(1)
• I = 8378
  II= 13450
  13450*5/100= 1345*1/2= 1345/2= 672.5
  III= 13450+675.5= 14125.5
  
  141255*5/1000= 141255*1/200= 28251/100= 282.51
  IV=14125.5+282.51 = 14408.01
  
  1440801*5/10000= 1440801*1/2*1000=1440.801/2=720.400
  V= 14408.01+720.400= 15128.410
  
  
  
• 10 years agoHelpfull: Yes(4) No(2)
• if 'P' is the principal amount then compound interest for rate of interest 'r' and time period 'n'...then amt after n years is A=P((1+r/100)^n)...in dis problem P=13450,n=3 yrs,r=5%...so A=13450(1.05^3)=15500.05625
• 10 years agoHelpfull: Yes(1) No(1)
• use compound interest formula for last 3years
  s=p(1+R/100)power n
  s=13450(1+5/100)power 3
  13450*(21/20)power 3=15570.1235
• 10 years agoHelpfull: Yes(1) No(0)
• Ans:15467(approx)
  13450*(15/100)=2017(approx)
  5th year cost=13450+2017
  15467
• 10 years agoHelpfull: Yes(0) No(2)