there are 8 flowers to be arranged in garland in which 4 flowers are not to be seperated find probability of arranging them?
a)960b)260c)1320d)595
i dint exactly rememberd options but dey wer some wat like this

• 4!(5!)
  4 flowers always come together so cinsider it as 1 flower and remaining four total 5 arrange it in 5! Ways and four flowers which always come together arrange in 4! Ways.
  Total no. Of ways multiply them 5!*4!
• 10 years agoHelpfull: Yes(45) No(9)
• 4 flowers which are always together can be considered as one SET,
  
  Therefore we have to arrange one SET ( 4 flowers ) and 4 other flowers into a garland.
  
  Which means, 5 things to be arranged in a garland.
  
  (5-1)!
  
  And the SET of flowers can arrange themselves within each other in 4! ways.
  
  Therefore
  
  (5-1)!*(4!)
  
  But, Garland, looked from front or behind does not matter. Therefore the clockwise and anti clockwise observation does not make difference.
  
  Therefore
  
  (5-1)! * (4!)/ 2
  
  = 288.
• 10 years agoHelpfull: Yes(24) No(2)
• 4 flowers always come together, so consider it as 1 and remaining four makes total 5. Now, for a circular arrangement if clockwise and anticlockwise arrangements are different, then from formula we get 1/2(n-1)! = 1/2 * 4!= 12. For each of these arrangements, those 4 flowers together make 4! arrangements, so its total of 12*4!=288
  
  
  
• 10 years agoHelpfull: Yes(14) No(1)
• Options are incorrect:
  5! * 4!= 120*24=2880 ans.
• 10 years agoHelpfull: Yes(10) No(2)
• totally 8 flowers .....
  4 flowers are always joined so it is consider us 1 flower
  so now totally 5 flowers
  so 4!*5!
• 10 years agoHelpfull: Yes(3) No(1)
• the number of ways to arrange 8 flowers are 8! , i.e n(s) = 8!
  E = event of ways arranging 8 flowers in which 4 flowers are always together
  i.e four flowers as together 1 & rest 4 , so total 5 flowers arrangement
  = 5! * 4! = 2880
  
  probability = n(E) / n(s)
  = 2880 / 40320 = 1/14
• 10 years agoHelpfull: Yes(3) No(2)
• when we talk about flower arrangement in garlend then total no of ways=(n-1)!/2.
  since here 4flowrs are always together then consider it as 1 then no of ways =
  (5-1)!/2,
  and 4flowers itshelf can be arrange in 4! ways . so the correct ans is=
  ((5-1)!/2)*4!=288 is correct ans.
• 10 years agoHelpfull: Yes(3) No(0)
• 4!5!
  
  the flowers to be together are considered as one,so the total ways to arrange 5!
  and the 4 flowers considered one will also arrange so multiply by 4!
• 10 years agoHelpfull: Yes(1) No(1)
• in question probability is asking ,so probability should be less then 1
  
• 10 years agoHelpfull: Yes(1) No(1)
• for flowers arrangement (n-1)!. so 4 flowers together as one unit and remaining 4 flowers total (5-1)! and 4 flowers can be arranged themselves as 4! waya..
  total (5-1)! * 4! ways==576
• 10 years agoHelpfull: Yes(1) No(2)
• Ans is not match 5!*4!=2880
  
• 10 years agoHelpfull: Yes(0) No(0)
• @all----> in question probability is asked
• 10 years agoHelpfull: Yes(0) No(0)
• probability=(5!*4!)/(8!)
• 10 years agoHelpfull: Yes(0) No(2)
• 4!*4!/2=288
  
• 10 years agoHelpfull: Yes(0) No(1)