A and B can do a piece of work in 18 and 9 days respectively. A does the work for a few days and left, then B continued for 6 days. How many days did A and B work together?

• A and B work together for 2days.
  A 1day work 1/18
  B 1day work 1/9
  Let A work x days.
  Then equation form is
  (x/18) + ((x+6)/9) = 1
  From this equation x value is 2.
  
• 10 years agoHelpfull: Yes(47) No(5)
• A 1day work=1/18
  B 1day work=1/9
  A+B 1day work=1/18+1/9 = 3/18 (1 work in 18/3 =6days)
  
  B continued for 6 days,
  so,B 6days work=6/9
  
  Total work done by A+B together = (1-6/9) = 3/9
  Hence,A+B
  3/18 work in 1day(from above )
  1 work in 18/3day=6day
  so,3/9 work in(6*3/9)= 2 days
  
  so,both A and B worked for 2 days..
  
  
• 10 years agoHelpfull: Yes(19) No(1)
• Simplest Way is to , take LCM of both the work that is A=18 & B=9 ie.{18}
  Now this is toal work that is to be done..
  if we divide A's work and B's work by this total work than we get A=1, and B=2
  =>than sum these 1days work of A and B i.e 3(this is Capability of there work in 1 day....)
  
  Now let A+B work is 3 no. of days they worked be x so, total work they done for x days is==> 3x
  again when A left remainig work done by B in 6 Days hence total work by B in 6 Days is 6X2 i.e 12
  
  now we no total work is 18.
  ie.
  3x + 12 = 18
  x=2 Ans:)
• 10 years agoHelpfull: Yes(8) No(0)
• a=18 and b=9
  a's 1 day work=1/18
  b's 1 day work=1/9
  
  a+b= 1/18+1/9 = 27/162=3/18=1/6
  
  a+b's 1 day work=1/6
  
  in 6 days b can complete
  
  1 1/9
  6
  
  6/9= 2/3 part of d work
  
  Remainng 1/3 was done by a+b
  
  1 1/6
  ? 1/3
  
  1/3*6/1= 2days
  
  so a+b worked for 2 days
• 10 years agoHelpfull: Yes(4) No(0)
• A --- 18 days
  B-----9 days
  
  Let the total work is 18 UNITS (i.e L C M 0f 18 and 9).
  
  1 day work of A--- (18/18) -units/day=1 u/d
  
  1 day work of B --- (18/9) units/day= 2 u/d
  
  now 6 days work of is --- 6*2= 12 units
  
  remaining work = 18-12=6.
  
  
  A and B worked Both === 6/(1+2)=2 days.
  
  
  
  
  
• 10 years agoHelpfull: Yes(4) No(0)
• A's 1 day work=1/18
  B's 1 day work=1/9
  both A and B's work in 1day =(1/18)+(1/9)
  =3/18
  =1/6
  so in 6days they will complete the work
• 10 years agoHelpfull: Yes(3) No(22)
• let A works for 'x' days
  now from the given problem x/18 + (x+6)/9 = 1
  we get x=2 so A worked for 2 days and B also worked for 2 days+ 6 days=8 days.
  So total work = 2+8=10 days
• 10 years agoHelpfull: Yes(1) No(0)
• it was clearly stated that B worked till the work gets completed. So consider B worked for X days and it was clearly stated that A worked 6 days less than B. So consider A worked for X-6 days and in question he said that work was completed so take 1 in RHS side.
  A's 1day work is 1/18.
  B's 1day work is 1/9.
  The equation is:
  (x-6)/18+(x)/9=1
  By solving above equation we get X=2.
• 6 years agoHelpfull: Yes(1) No(0)
• A's one day work=1/18
  B's one day work=1/9
  A+B's one day work=1/18+1/9=3/18
  B's 6 days work=6*1/9=6/9
  remaining work=1-6/9=3/9
  now 3/18 work in one day
  3/9 work in how many days?
  =3/9*1/3/18=1/3/1/6=1/3*6=2days
  
• 10 years agoHelpfull: Yes(0) No(0)
• One day work of A=1/18
  One day work of B=1/9
  1/18*X+1/9(6+X)=1
  X=2
• 10 years agoHelpfull: Yes(0) No(0)
• Lcm of work=18 unit
  A work is=1unit per day
  B wwork is=2 unit per day
  A&B one day work=3 unit per day
  So 6*3=18 unit ,so ans is 6
• 9 years agoHelpfull: Yes(0) No(1)
• A 1day work 1/18
  B 1day work 1/9
  B 's 6 days work 2/3
  Remaining work will be done by (A+B) =1-2/3=1/3
  (A+B)'s one day work is (1/18 +1/9)=1/6
  A+B)'s work togethe for ((1/3)/(1/6)=2 days
  
• 9 years agoHelpfull: Yes(0) No(0)
• A alone can complete work in 18 days and B alone can complete work in 9 days.
  Now, let A and B work together for 'X' days after which A leaves. Then B alone works for 6 days and finished the work. Hence the combined work of A and B is equal to 3 days of B alone.
  One day's work of A= 1/18, One day's work of B = 1/9.
  1/18 *X + 1/9 *X = 1/9 * 3
  X+2X/ 18= 1/3
  3X = 18/3
  X= 18/9
  X= 2
• 7 years agoHelpfull: Yes(0) No(0)
• [mn-p(m-n)]/(m+n) where m=A's working days
  n = B's working days and after p days A LEFT
  by putting these values
  [(18*9)-p(18-9)](18+9)=6
  p=2 days
• 7 years agoHelpfull: Yes(0) No(0)
• A and B work together for 2days.
  A 1day work 1/18
  B 1day work 1/9
  Let A work x days.
  Then equation form is
  (x/18) + ((x+6)/9) = 1
  From this equation x value is 2.
• 5 years agoHelpfull: Yes(0) No(0)