world+trade=center than find the value of c+e+n+t+e+r+?

• A=0 C=1 D=4 E=2 L=8 N=9 O=3 R=6 T=7 W=5
  
  From this c+e+n+t+e+r = 1+2+9+7+2+6 =27.
  
• 10 years agoHelpfull: Yes(9) No(16)
• The correct answer is 18
  A=1,B=2,....Z=26
  W*O*R*L*D = 23*15*18*12*4 = 298080
  T*R*A*D*E= 20*18*1*4*5 =7200
  (WORLD)+(TRADE) =
  298080+7200=305280=CENTER
  3+0+5+2+8+0=18
• 10 years agoHelpfull: Yes(9) No(26)
• can any one explain it...
• 10 years agoHelpfull: Yes(4) No(0)
• W O R L D
  5 3 6 8 4
  
  + T R A D E
  7 6 0 4 2
  
  ==================
  
  C E N T E R
  1 2 9 7 2 6 C + E + N + T + E + R = 27
• 7 years agoHelpfull: Yes(3) No(3)
• nine+fine=wives solve
  
• 9 years agoHelpfull: Yes(2) No(2)
• http://www.tkcs-collins.com/truman/alphamet/alphamet.shtml#Sentences_phrases
  
  refer for this type of qs.
• 8 years agoHelpfull: Yes(2) No(2)
• How did you solve it?????Don't give such random numbers.Provide explanation for why did you think it was right.Hope I'd see explanation soon.
• 6 years agoHelpfull: Yes(2) No(0)
• c+e+N+T+E+R = 30
• 10 years agoHelpfull: Yes(1) No(6)
• can any one explain it plzplzpzzzzzzz.....
• 10 years agoHelpfull: Yes(1) No(4)
• C+E+N+T+E+R=20
• 7 years agoHelpfull: Yes(0) No(2)
• c+e+n+t+e+r=65
• 6 years agoHelpfull: Yes(0) No(1)
• Here w=5, o=3, r=6, l=8, d=4
  T=7, r=6, a=0, d=4, e=2
  Hence c+e+n+t+e+r=1+2+9+7+2+6=27.
• 5 years agoHelpfull: Yes(0) No(0)
• The following alphametic puzzle:
  
  WORLD
  +TRADE
  ------
  CENTER
  
  has 1 solution.
  
  It is:
  
  53684 A=0 C=1 D=4 E=2 L=8 N=9 O=3 R=6 T=7 W=5
  +76042
  ------
  129726=27
• 5 years agoHelpfull: Yes(0) No(0)