please find the solution..
In an isosceles triangle, the sides are13cm,13cm,10cm which is inscribed insiade acircle. Find the radius of the circle.2)A

• sides are, a=13,b=13,c=10
  s=(a+b+c)/2 =(13+13+10)/2=18
  area of triangle=[18(18-13)(18-13)(18-10)]^1/2 = (18*5*5*8)^1/2 =60 cm^2
  R be the radius then it will be circumradius of triangle
  R=(a*b*c)/(4*area of triangle)
  R=(13*13*10)/(4*60)=7.04cm
• 10 years agoHelpfull: Yes(3) No(5)
• theorem
  perpendicular^2 = 13^2-5^2 = 169-25 = 144
  perpendicular^2 = 12
  radius = 6 cm
  ans. >>>>>>>> 6 cm
• 10 years agoHelpfull: Yes(2) No(1)
• 10 : 13 :: 13 d
  10d=169
  10(2r)=169
  20r=169
  r=169/20
  r=8.45
• 10 years agoHelpfull: Yes(0) No(1)