kabir requires 10days less than Akshay to complete a work. satyam takes 15days more than Akshay to do same work. if kabir & akshay takes 12 days to finish the work In how many days satyam & akshay will finish that work.?

• ans is 18
  let w.d by akshay be x.
  now kabir takes 10 day less than akshay to complete the work.
  now (1/x+1/x-10)*12=1 we get x =30.
  time taken by satyam= 30+15=45
  time taken by satyam and akshay.
  (1/45+1/30)*x=1 we get x=18
• 10 years agoHelpfull: Yes(4) No(0)
• 18 days;
  kabir=x days,akshay=x+10 days,sathyam=x+25days
  so each day worx is 1/x,1/(x+10);1/(x+25) respectively
  so 12 days for kabir and akshay=12(1/x+1/x+10)= total work so x=20days
  then y((1/x+10)+(1/x+25))=1
  so y=18days.
• 9 years agoHelpfull: Yes(1) No(1)
• K=a-10
  s=a+15
  k's 1 day work=1/a-10
  s=1/a+15
  
  k+s=1/(a-10)+1/(a+15)
  
  a+15+a-10/(a2+15a-10a-150)=1/12
  
  2a+5/(a^2+5a-150)=1/12
  24a+180=a^2+5a-150 -150 = -10*(+15)
  19a+330=a^2
  
  a^2-19a-330=0 -330 = -30 *(+ 11)
  (a-30)(a+11)=0
  
  a=30
  
  Akshay ll complete the work in 30 days
  
  Kabir=30-10=20
  Sathya=30+15=45
  
  
  s+a 's 1 day work =1/45+1/30
  = 75/1350 = 15/270 = 5/90= 1/18
  
  Sathyam and akshay ll complete in 18 days
  
  
• 10 years agoHelpfull: Yes(0) No(1)