(40*40*40-31*31*31)/(40*40+40*31+31*31)=?

• ANSWER : 9
  
  SOLUTION :
  
  Assume a=40 & b=31
  Now,
  (a^3 - b^3)/(a^2 + ab + b^2) = (a-b)(a^2 ab + b^2)/(a^2 ab + b^2) = (a-b)
  = (40-31) = 9
• 13 years agoHelpfull: Yes(7) No(1)
• we know (a^3-b^3)=(a-b)(a^2+ab+b^2)
  so considering given relation
  answer will be a-b i.e 40-31=9
• 13 years agoHelpfull: Yes(2) No(0)