Q. A number 'Z' contains all the digits from 1 to 9 exactly once. Z is divisible by 99. what will b the number on its hundredth place.
Option
a) 1
b) 2
c) 3
d) 4

• Let d digits be abcdefghi
  if it is divisible by 99 , it shud be divisible by both '9' nd '11'
  divisible by 11 means ----> (a+c+e+g+i)-(b+d+f+h) / 11
  --------------------------> (7+5+6+2+8)-(1+3+4+9) = 28-17 which is divisible by 11
  
  so the number is 715364298
  
  nd the 100th digit is "2"
• 10 years agoHelpfull: Yes(16) No(22)
• more than one answers are possible like
  142738596
  542738196
  541738296
  541728396
  
• 9 years agoHelpfull: Yes(7) No(1)
• can i know the right answer if its wrong...
• 10 years agoHelpfull: Yes(5) No(3)
• with all due respect wt abt 917365482 i got this ans
• 10 years agoHelpfull: Yes(2) No(4)
• suppose digits be abcdefghi
  if it is divisible by 99 ,
  it shud be divisible by both '9' (7+5+6+2+8)+(1+3+4+9) = 45 which is divisible by 9
  
  and
  divisible by 11 means is (a+c+e+g+i)-(b+d+f+h)/11
  (7+5+6+2+8)-(1+3+4+9) = 28-17 which is divisible by 11
  
  so the number is 715364298
  
  so the 100th digit is 2
• 10 years agoHelpfull: Yes(2) No(4)
• approach is right but in the question not mentioned that number is greatest or smallest .so question is incomplete because if u find any no which divisible by 99 if u exchange the no from odd place sum of the digits of odds place always be 28 and the even place 17 see ur self in above examples
  like 7+5+6+2+8 or if exchang the no 5+7+6+2+8 or 2+8+7+5+6 and similar for even place.
• 6 years agoHelpfull: Yes(2) No(0)
• this can be answer 214365789 then 100 digit is 7
  
• 10 years agoHelpfull: Yes(1) No(2)
• but there is no such option...
• 10 years agoHelpfull: Yes(1) No(1)
• At 100th place we can put 9,8,6,4,1 .Among the options 4 can be the answer.
• 10 years agoHelpfull: Yes(1) No(0)
• 99 = 9×11 where 9 and 11 are coprime. Therefore, if a number is divisible by 9 and 11, it is divisible by 99 also
  
  Here all the digits from 1 to 9 are used exactly once. 1+2+...+9 = 45. 45 is divisible by 9.
  => any number formed by using the digits 1 to 9 exactly one is divisive by 9
  
  Hence, any number formed by using 1 to 9 exactly once is divisible by 99 if the same is divisible by 11
  
  For number to be divisible by 11, [Sum of odd numbered digits] - [sum of even numbered digits] = 0 or divisible by 11
  
  for example, (5+6+7+2+8) - (1+3+4+9) = 11
  
  Hence, 516374298 is a number which is divisible by 99
  In this case, the digit at hundredth place is 2
  
  But this is not the only answer. We can get other numbers also in a similar way such as 245837196 and accordingly different answers for the hundredth place digit(like 1 in this case)
  
• 7 years agoHelpfull: Yes(1) No(1)
• 99 = 9×11 where 9 and 11 are coprime. Therefore, if a number is divisible by 9 and 11, it is divisible by 99 also
  
  Here all the digits from 1 to 9 are used exactly once. 1+2+...+9 = 45. 45 is divisible by 9.
  => any number formed by using the digits 1 to 9 exactly one is divisive by 9
  
  Hence, any number formed by using 1 to 9 exactly once is divisible by 99 if the same is divisible by 11
  
  For number to be divisible by 11, [Sum of odd numbered digits] - [sum of even numbered digits] = 0 or divisible by 11
  
  for example, (5+6+7+2+8) - (1+3+4+9) = 11
  
  Hence, 516374298 is a number which is divisible by 99
  In this case, the digit at hundredth place is 2
  
  AND
  
  But this is not the only answer. We can get other numbers also in a similar way such as 245837196 and accordingly different answers for the hundredth place digit like 1
• 7 years agoHelpfull: Yes(1) No(0)
• number is divisible by 99 means divisible by 9 and 11 both
  number formed by digit 1 to 9 i.e (1+2+3+4+5+6+7+8+9)=45 is always divisible by 9
  but not divisible by 11
  condition for divisibility by 11 is-(sum of odd places number-sum of even places number)
  so here, hit and trial method
  digit taken from 1 to 9
  for e.g (5+6+7+8+2)-(3+4+1+9)=11
  is divisible by 11
  so number is 536471298
  hundredth place digit is 2
• 7 years agoHelpfull: Yes(1) No(0)
• wt abt 928675341
• 10 years agoHelpfull: Yes(0) No(1)