Q. If CROSS + ROADS = DANGER then D+A+N+G+E+R=?
Option
a)31
b)21
c)11
d)16

• 96233+62513=1+5+8+7+4+6=31
  
• 10 years agoHelpfull: Yes(14) No(3)
• C R O S S
  + R O A D S
  D A N G E R
  
  clearly d=1 becoz max. possible carry is 1. s+s=r means r is even, assume r=6 then s=3.
  now s+d=e ==> e=4
  now we are left with 0,2,5,6,7,8,9
  assume c=9, as c+r=a ===>a=5
  o+a=g , assume o=2 then g=7
  at last n will be 8.
  
  ******All assumptions are made by hit and trial,i have written only the correct cases
  so D+A+N+G+E+R=31
• 10 years agoHelpfull: Yes(7) No(2)
• plz explain clrly...
• 10 years agoHelpfull: Yes(3) No(2)
• please explain it...
  
• 10 years agoHelpfull: Yes(2) No(1)
• USA
  USSR
  ------ hence p=1. & E=0 and since E not equal to U. so U=9 and adding a carry
  PEACE 1 with it to 10 as PE. now U+s=10+A to produce a carry for the lastterm
  i.e 9+S=10+A.....(1)
  again E=0, so A+R=10, hense it produce a carry 1,which adds up with S+S to make C, i.e 2S+1=c, s9, but s=0,4 not possible as it gives C=1,9, which is not possible as P=1 & U=9. so S may be 1,2,3. but S=1 gives A=0 not possible, S=2 gives A=1 not possible. so only S=3 is possible. now S=3 gives A=2 & C=7. A+R=10, R=8. P+E+A+C+E=1+0+2+7+0= 10(Ans.)
  
• 10 years agoHelpfull: Yes(2) No(4)
• b (d+a+n+g+e+r=1+0+4+6+2+8=21)
• 10 years agoHelpfull: Yes(1) No(3)
• pls help with the procedure to follow for solving these ques??
• 10 years agoHelpfull: Yes(0) No(0)
• can anyone explain these type of ques clearly??
• 9 years agoHelpfull: Yes(0) No(0)
• ans:D+A+N+G+E+R=31
• 9 years agoHelpfull: Yes(0) No(0)