Q. A certain number of bullets were shared by 3 people equally.Each of them fired 4 bullets and the sum of the remaining bullets was equal to the initial share each had got. What was the initial number of bullets?

• lets each one got x bullets .
  so total no of bullets= 3x.
  a/c to question each person used 4 bullets each one has remains with x-4 bullets.
  so (x-4)3=x.
  x=6.
  so total no of bullets =3x =3*6 =18.
• 10 years agoHelpfull: Yes(67) No(1)
• total bullets=x
  share of each x/3
  remaining bullets
  3*(x/3-4)=x/3
  x=18 ans.
• 10 years agoHelpfull: Yes(10) No(1)
• 18
  let "x" was d initial no. of bullets
  each got x/3
  each fired 4,so total fired bullets=4*3=12
  x-12=x/3
  x=18
  
• 10 years agoHelpfull: Yes(6) No(1)
• if x,y&z are the 3 people, A is the the no of bullets shared eualy.
  X=Y=Z=A.
  tn each of them fired 4 bullets,and remaining bullets with them is
  (X-4),(Y-4),(z-4)
  tn this above sum is equal to initial share mean "A" value.
  tn we can write
  (A-4)+(A-4)+(A-4)=A (bcz: starting X=Y=Z=A)
  2A=12
  A=6
  ans:6
  
  manjula r, bangalore
• 10 years agoHelpfull: Yes(1) No(6)
• 18 is the correct ans.... let each share is x,
  then... (4.3) + x = 3.x
  x=6,
  total initial bullets 3.6=18
• 10 years agoHelpfull: Yes(1) No(1)
• no of people=3
  (x-4)3=x
  x=6
  3x=3*6=18
• 8 years agoHelpfull: Yes(0) No(0)