Q. Please solve it as early as possible A ladder rests against a wall at angle A to the horizontal,if foot is pulled away from the wall through a distance 'a' so that it slides a distance b down the wall making an angle B with the horizontal, show that
a/b = cosA - cosB/SinB - SinA

• let l be the length of ladder then l=(x^2+y^2)
  after pulling,disatances will be (x+a)& (y-b)
  1st case
  x/sin(90-A)= y/sinA = l/sin90 => sinA=y/l & cosA=x/l
  
  2nd case
  (x+a)/sin(90-B)=(y-b)/sinB = l/sin90 => sinB=(y-b)/l & cosB=(x+a)/l
  
  so (cosA-cosB)/(SinB-SinA)=[ x/l - (x+a)/l ]/[(y-b)/l - y/l] = a/b
  
• 11 years agoHelpfull: Yes(2) No(0)