Q. 1,2,1,2,2,1,2,2,2,1,2,2,2,2.... then sum of 1230 terms....???

• 1230 terms contain 49 1's and remaining 2's
  so 1181*2+49 = 2411
• 10 years agoHelpfull: Yes(5) No(0)
• I think sum is 1231 mistake in question
  
  (2*598)+(1*35)=1231
  
  term is 598+35=633
• 10 years agoHelpfull: Yes(0) No(8)